Question

solve 2(y+1)^2-5(y+1)=12​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

2(y+1)^2 -5(y+1)=12

2 (y^2+2y+1^2)-5y-5=12

2y^2+4y+2 -5y-5 =12

2y^2 -y-3 =12

2y^2-y =15

2y^2-y-15=0

by now middle spilt

2y^2 -(6-5)y-15

2y^2-6y+5y-15

2y(y-3) +5(y-3)

(y-3) (2y+5)

since y has two value

y=3

or

y =-5/2