Math, asked by abha5152, 1 year ago

Solve 20% of (P+Q)=50% of (P-Q), find P:Q = ?

Answers

Answered by Anonymous
3
Given :

20% of (P + Q) = 50% of (P - Q)

If we remove of, there comes a sign of multiplication ( × ) and if we remove %, the number will be divided by 100.

\therefore

\dfrac{20}{100} × (P + Q) = \dfrac{50}{100} × (P - Q)

\dfrac{2{\cancel{0}}}{10{\cancel{0}}} × (P + Q) = \dfrac{5{\cancel{0}}}{10{\cancel{0}}} × (P - Q)

\dfrac{2}{10} × (P + Q) = \dfrac{5}{10} × (P - Q)

\dfrac{2}{{\cancel{10}}} × (P + Q) = \dfrac{5}{{\cancel{10}}} × (P - Q)

2 (P + Q) = 5 (P - Q)

Open the ( ) brackets, we get

2P + 2Q = 5P - 5Q

2P - 5P = - 5Q - 2Q

- 3P = - 7Q

{\cancel{-}} 3P = {\cancel{-}} 7Q

3P = 7Q

Rearranging it, we get

\dfrac{P}{Q} = \dfrac{7}{3}

\therefore

P : Q = 7 : 3

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