Math, asked by rabia1983, 6 months ago

solve 21a^4-14a^2+42/7a^2​

Answers

Answered by Miaruthmasongsantol
1

Answer:

Step-by-step explanation:

21a^4-14a^2+42/7a^2

=21a^4-14a^2+42a^2/7

=3a^4-2a^2+6a^2

=3a^4+4a^2

Similar questions