Solve:
27p3 - 1/216 - 9/2p2 1/4p
Answers
Answered by
14
HEY!!
27p3 - 1/216 - 9/2p2 + 1/4p
(3p)3 - 1/ (6)3 - 3 (3p)2 (1/6) + 3 (3p) (1/6)2
On camparing the above expansion with the identity (a+b)3 = a3 + b3 + 3a2b+ 3ab2 we get,
(3p - 1/6)3
27p3 - 1/216 - 9/2p2 + 1/4p
(3p)3 - 1/ (6)3 - 3 (3p)2 (1/6) + 3 (3p) (1/6)2
On camparing the above expansion with the identity (a+b)3 = a3 + b3 + 3a2b+ 3ab2 we get,
(3p - 1/6)3
Answered by
9
hy
here is your answer
=================
*************************
➡27p³- 1/216 - 9/2p2 + 1/4p
➡(3p)³ - 1/ (6)³ - 3 (3p)²(1/6) + 3 (3p) (1/6)²
➡On camparing the above expansion with the identity
➡(a+b)³= a³+ b³+ 3a²b+ 3ab²
➡ we get,
➡(3p - 1/6)³
here is your answer
=================
*************************
➡27p³- 1/216 - 9/2p2 + 1/4p
➡(3p)³ - 1/ (6)³ - 3 (3p)²(1/6) + 3 (3p) (1/6)²
➡On camparing the above expansion with the identity
➡(a+b)³= a³+ b³+ 3a²b+ 3ab²
➡ we get,
➡(3p - 1/6)³
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