Math, asked by Anonymous, 1 year ago

Solve:

27p3 - 1/216 - 9/2p2 1/4p

Answers

Answered by Suryavardhan1
14
HEY!!

27p3 - 1/216 - 9/2p2 + 1/4p

(3p)3 - 1/ (6)3 - 3 (3p)2 (1/6) + 3 (3p) (1/6)2


On camparing the above expansion with the identity (a+b)3 = a3 + b3 + 3a2b+ 3ab2 we get,

(3p - 1/6)3
Answered by Anonymous
9
hy
here is your answer
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➡27p³- 1/216 - 9/2p2 + 1/4p

➡(3p)³ - 1/ (6)³ - 3 (3p)²(1/6) + 3 (3p) (1/6)²

➡On camparing the above expansion with the identity

➡(a+b)³= a³+ b³+ 3a²b+ 3ab²

➡ we get,

➡(3p - 1/6)³
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