Question

SOLVE

27p3 - 1/216 - 9/2p2 1/4p

Answer 1

$27 {p}^{3} - \frac{1}{216} - \frac{9}{2} {p}^{2} + \frac{1}{4} p \\ \\ = {(3p)}^{3} - ( { \frac{1}{6} )}^{2} - 3(3p)( \frac{1}{6} )(3p - \frac{1}{6} ) \\ \\ \\ = {(3p - \frac{1}{6}) }^{3} \\ \\ = (3p - \frac{1}{6} )(3p - \frac{1}{6} )(3p - \frac{1}{6} )$