solve 29th question please
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In oswaal pg no 182
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Step-by-step explanation:
Length of the field=20m
Breadth of the field =14m
Volume of the well =volume of raise in field (i)
There fore,volume of cylindrical well=πrrh
=22÷7×7÷2×7÷2×10
=385cubic m
From(i),
Volume for raise in field = l×b× h=385
14×20×h=385
385÷14×20=h
This implies height of raise in field =1.35m
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