Question

Solve :
2cos^2 theta + 2√2sin theta = 3

Answer 1

Answer:

We have 2cos

2

θ+3sinθ=0

2(1−sin

2

θ)+3sinθ=0

2sin

2

θ−3sinθ−2=0

(sinθ−2)(2sinθ+1)=0

2sinθ+1=0 [∵sinθ



=2]

sinθ=−

2

1

=sin(−

6

π

)

⇒ θ=nπ+(−1)

n

(−

6

π

), n∈Z

θ=nπ+(−1)

n

6

π

, n∈Z