Question

Solve..
2cos^2x + 3 sinx=0​

Answer 1

Step-by-step explanation:

2cos²x+3sinx=0

2(1-sin²x)+3sinx=0

2-2sin²x+3sinx=0

2sin²x-3sinx-2=0 (multiplying by (-1)) on eachterm))

let y=sinx

2y²-3y-2=0

2y²-4y+y-2=0

2y(y-2)+1(y-2)=0

(2y+1)(y-2)=0

y=(-1/2),2

sinx=2 does not exist

sinx=(-1/2)

x=sin^-1(-1/2)= (-30°)