Math, asked by mitch67, 1 year ago

Solve: 2sin^x = cos-x. 0 < x < 1​

Answers

Answered by artistvikash1
0

Answer:

2sin^2x=cosX

then

2(1-cos^2x)=cosX

2cos^2x+cosx-2=0

ok

follow me

guys

Similar questions