Question

solve 2x+1 / 3x+5 = 11/20 fine the value of x​

Answer 1

$\dfrac{2x + 1}{3x + 5} = \dfrac{11}{20}$

Cross multiply

☛ 20(2x + 1) = 11(3x + 5)

Open the brackets

☛ 40x + 20 = 33x + 55

Move the like terms

☛ 40x - 33x = 55 - 20

Subtract

☛ 7x = 35

Divide both the sides by 7

☛ x = 5


∴ The value of x is $\pink{\boxed{\pink{\boxed{\red{5}}}}}$

Answer 2

$\underline{\underline{\bold{Question:}}}$

$\bold{If\quad\dfrac{2x+1}{3x+5}=\dfrac{11}{20}\:,then\:find\:the\:value\:of\:x.}$

$\underline{\bold{Solution:}}$

$\implies{\bold{\dfrac{2x+1}{3x+5}=\dfrac{11}{20}}}\\\\\\\implies{\bold{(2x+1)20=(3x+5)11}}\\\\\\\implies{\bold{40x+20=33x+55}}\\\\\\\implies{\bold{40x-33x=55-20}}\\\\\\\implies{\bold{7x=35}}\\\\\\\implies{\bold{x=\dfrac{35}{7}=5.}}\\\\\\\boxed{\boxed{\bold{The\:value\:of\:x=5.}}}$

$\underline{\bold{Verification\:,}}$

$\underline{\bold{From\:LHS,}}\\\\\\\bold{=\dfrac{2x+1}{3x+5}}\\\\\\\underline{\bold{Put\:the\:value\:of\:x.}}\\\\\\\bold{=\dfrac{2{\times}5+1}{3{\times}5+5}}\\\\\\\bold{=\dfrac{10+1}{15+5}=\dfrac{11}{20}.}\\\\\\\bold{LHS=\dfrac{11}{20}=RHS.}$