Question

solve 2x^2-3x-2=0 by using the quadratic formula​

Answer 1

Answer:

2x^2-3x-2=0

we will first find its zeroes

2x^2-4x+1x-2

2x(x-2)+1(x-2)

(2x+1) (x-2)

x=-1/2 and x=2 are the zeroes of it

alpha + beta =-b/a

2-1/2=-b/a

4-1/2=-b/a

3/2=-b/a

-3/2=-b/a

alpha x beta = c/a

(2)(-1/2)=c/a

-2/2=c/a

this the answer according to me.