Question

solve 2x^2 -4x -345 using quadratic formula​

Answer 1

2x2-4x-345

Final result :

2x2 - 4x - 345

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(2x2 - 4x) - 345

Step 2 :

Trying to factor by splitting the middle term

2.1 Factoring 2x2-4x-345

The first term is, 2x2 its coefficient is 2 .

The middle term is, -4x its coefficient is -4 .

The last term, "the constant", is -345

Step-1 : Multiply the coefficient of the first term by the constant 2 • -345 = -690

Step-2 : Find two factors of -690 whose sum equals the coefficient of the middle term, which is -4 .

-690 + 1 = -689

-345 + 2 = -343

-230 + 3 = -227

-138 + 5 = -133

-115 + 6 = -109

-69 + 10 = -59

-46 + 15 = -31

-30 + 23 = -7

-23 + 30 = 7

-15 + 46 = 31

-10 + 69 = 59

-6 + 115 = 109

-5 + 138 = 133

-3 + 230 = 227

-2 + 345 = 343

-1 + 690 = 689

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

2x2 - 4x - 345