Question

solve :
2x^2 - 7x + 3 = 0
by -b + or - root of b^2 - 4ac / 2a
(quadratic equation)

please i need it fast.

Answer 1

Answer:

hope this helps.........

Answer 2

Answer: x=3, 1/2

Step-by-step explanation:

$2 {x}^{2} - 7x + 3 = 0 \\ \\ a = 2 \\ b = - 7 \\ c = 3 \\ \\ x = \frac{ - b( + - ) \sqrt{ {b}^{2}- 4ac } }{2a} \\ x = \frac{- ( - 7)( + - ) \sqrt{ { - 7}^{2} - 4(2)(3) } }{2(2)} \\ x = \frac{7( + - ) \sqrt{49 - 24} }{4} \\ x = \frac{7( + - ) \sqrt{25} }{4} \\ x = \frac{7( + - )5}{4} \\ \\ \\ x = \frac{7 + 5}{4} \\ x = \frac{12}{4} \\ x = 3\\ \\ or \\ x = \frac{7 - 5}{4} \\ x = \frac{2}{4} \\ x = \frac{1}{2}$

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