Question

Solve : (2x – 3)/(3x – 5) = ½​

Answer 1

(2x – 3)/(3x – 5) = ½ can be written as

(2x – 3)=(3x – 5)×½

(2x – 3)×2=(3x – 5)

4x -- 6 = 3x -- 5

4x -- 3x = 6 -- 5

x = 1

HOPE THIS IS HELPFUL TO YOU

Answer 2

Given: The equation is$(2x -3)/(3x - 5) =\frac{1}{2}$.

We have to solve the above equation.

• By using the Bodmas rule, we are solving the above equation.
• As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

$(2x -3)/(3x - 5) =\frac{1}{2}$

$=>\frac{(2x-3)}{(3x-5)} =\frac{1}{2} \\\\=>2\times (2x-3)=1\times (3x-5)\\=>4x-6=3x-5\\=>4x-3x=-5+6\\=>x=1$

Hence, the value of $x$will be$1$.