Question

Solve:(2x+3)(x-4)=(2x-3)(x+3)

Answer 1

(2x + 3) × (x - 4) = (2x - 3) × (x + 3)

Multiply the brackets

☛ 2x² - 8x + 3x - 12 = 2x² + 6x - 3x - 9

Cancel the equal terms of 2x² on LHS and 2x² on RHS

☛ -8x + 3x - 12 = 6x - 3x - 9

Collect the like terms together

☛ -5x - 12 = 3x - 9

Move the terms

☛ -5x - 3x = -9 + 12

Calculate

☛ -8x = 3

Dividing both thw sides by -8, we get

☛ x = -3/8

∴ The value of x is $\boxed{\boxed{\dfrac{-3}{8}}}$

Answer 2

$\underline{\mathfrak{\huge{The\:Question:}}}$

Solve : $\tt{(2x + 3) (x - 4) = (2x - 3) (x + 3)}$

$\underline{\mathfrak{\huge{Your\:Answer:}}}$

We'll start with opening up these given brackets

$\tt{2x^{2} - 8x + 3x - 12 = 2x^{2} + 6x - 3x - 9}$

Since the term $\sf{2x^{2}}$ is common in both, the left hand side and the Right Hand Side, we can simply cancel it out. The left equation is :

=》 $\tt{3x - 8x - 12 = 6x - 3x - 9}$

Take all the variables on the left side, and the constants on the right side and solve :

=》 $\tt{3x - 8x - 6x + 3x = 12 - 9}$

Do the necessary operations on the numbers :

=》 $\tt{(-8x) = 3}$

Take (-8) on the right side :

=》 $\tt{x = - \frac{3}{8}}$