solve √2x+√3y=0 and √3x-√8y=0 using substitution method
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hey here is your answer
√2x+√3y=0.......(1)
√3x-√8y=0
√3x=√8y
x=√8y/√3.......(2)
Substituting value of x in equation (1)
√2(√8y/√3)+√3y=0
√16y/√3+√3y=0
4y+3y/√3=0
7y=0
y=0
Substituting value of y in equation (2)
x=√8(0)/√3=0
I think my answer is capable to clear your confusion
.
√2x+√3y=0.......(1)
√3x-√8y=0
√3x=√8y
x=√8y/√3.......(2)
Substituting value of x in equation (1)
√2(√8y/√3)+√3y=0
√16y/√3+√3y=0
4y+3y/√3=0
7y=0
y=0
Substituting value of y in equation (2)
x=√8(0)/√3=0
I think my answer is capable to clear your confusion
.
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