Math, asked by SivaAR, 7 months ago

Solve 2x+3y=13 and 4x-y=12.
using elimination method.
pls dont answer if you dont know.​

Answers

Answered by vikeshjee
1

Answer:

x=7/2

y=2

Step-by-step explanation:

2x+3y=13____________eq1

4x-y=12

12x-3y=36___________________eq2

add eq1 and eq2

2x+12x+3y-3y=13+36

14x=49

x=49/14

x=7/2

4x-y=12

putting x= 7/2

4(7/2)-y=12

14-y=12

-y=12-14

-y= -2

y=2

method:-2

2x+3y=13

2x=13-3y

x=(13-3y)/2

4x-y=12

putting x=(13-3y)/2

4((13-3y)/2)-y=12

2(13-3y)-y=12

26-6y-y=12

-7y=12-26

y=-14/-7

y=2

x=(13-3y)/2

x=(13-3(2))/2

   =13-6/2

    =7/2

Answered by sabarimalai1978
2

Answer:

x=7/2

y=2

Step-by-step explanation:

2x+3y=13.............(i)

4x-y=12...............(ii)

From equation......(i)

2x+3y=13

multiple by -2

-4x-6y=-26

-4x-6y=26

4x- y =12

-7y =-14

y. =2

substitute y in equation.........(i)

2x+3y=13

2x+3(2)=13

2x+6 =13

2x =7

x =7/2

I Hope this is helpful to you!!!!!

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