solve 2x+3y=5 and x-2y-3=0
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Answer:
2x+y=5.........(i)
x+3y=5..........(ii)
x−2y=0...........(iii)
From (iii) we get, x=2y
Substituting this value in (ii) we get-
2y+3y=5⇒5y=5⇒y=1
Hence, x=2y=2×1=2
Thus, the solution of (ii) and (iii) is x=2,y=1
Putting this value in LHS of equation (i) we get-
LHS=2(2)+1=4+1=5=RHS
Thus, x=2,y=1 also satisfies equation (i). Hence, all three equations have a unique solution which is x=2,y=1, i.e- the given system of equations has only one solution.
Answered by
0
Answer:
0
Step-by-step explanation:
-7y + 14 = 10.
+2x + 3y = 5
+ 1x - 2y-3=o
___________
- 7y + 14 = 0
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