Math, asked by NishthaMadahar, 1 year ago

solve 2x^4-5x^2+3 take x^2=y

Answers

Answered by usp488
1
= 2x^4-5x^2+3
= 2(x^2)^2-5(x^2)+3
= 2y^2-5y+3
= 2y^2-(3y+2y)+3
= 2y^2-3y-2y+3
= y(2y-3)-1(2y-3)
= (2y-3) (y-1)
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