Math, asked by kanishka9419, 2 months ago

Solve: 2x² - 2√6x +3=0

Answers

Answered by bangtanssonyondan

3

Step-by-step explanation:

Given

${2x}^{2} - 2 \sqrt{6x} + 3 = 0$

${2x}^{2} - 1 \sqrt{6x } - 1 \sqrt{6x} + 3$

$\sqrt{2x} ( \sqrt{2x} - \sqrt{3} ) - \sqrt{3} ( \sqrt{2x} - \sqrt{3} )$

$( \sqrt{2x} - \sqrt{3} ) ( \sqrt{2x} - \sqrt{3} )$

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