solve 2x² - 4x + 3 =0
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2x^2 - 4x +3 =0
comparing equation with ax^2 - bx +c=0
a= 2 , b= -4 and c= 3
we know that,
D=b^2 -4ac
= (-4)^2 -4×2×3
= 16 - 24
= -8
Since,D<0
So, the given equation has no real roots.
Answered by
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Step-by-step explanation:
Given equation 2 x ^2 - 4 x + 3 =0.
Compare to the quadratic form a x ^2 + b x + c = 0.
a = 2, b = - 4, c = 3.
x = [- b ± √(b ^2 - 4ac]/2a
x = [ 4 ± √(16 - 4*2*3)]/4
x = [4 ± √(16 - 24)]/4
x = [4 ± √-8 ]/4
i^2 = - 1.
x =[ 4 ± √8i^2]/ 4
x =[4 ± 2√2i^2]/ 4
x =[2 ± √2i] / 2
x = [ 1 ± i /√2 ]
x =1 + i / √2 and x =1 - i / √2
Solution : x = 1 + i /√2 and x = 1 - i /√2.
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