Solve 2x²+7x+3 with factor by splitting the middle term
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ANSWER:
- Zeros are -3 and -1/2.
GIVEN:
- P(x) = 2x²+7x+3
TO FIND:
- Factorise the above expression.
SOLUTION:
=> 2x²+7x+3 = 0
=> 2x²+6x+x+3 = 0
=> (2x²+6x)+(x+3)= 0
=> 2x(x+3) +1(x+3) = 0
=> (x+3)(2x+1)= 0
Either (x+3) = 0
=> x = (-3)
Either (2x+1) = 0
=> 2x = -1
=> x = -1/2
NOTE:
Some important formulas:
(a+b)² = a²+b²+2ab
(a-b)² = a²+b²-2ab
(a+b)(a-b) = a²-b²
(a+b)³ = a³+b³+3ab(a+b)
(a-b)³ = a³-b³-3ab(a-b)
a³+b³ = (a+b)(a²+b²-ab)
a³-b³ = (a-b)(a²+b²+ab)
(a+b)² = (a-b)²+4ab
(a-b)² = (a+b)²-4ab
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