Solve 2xy/x+y=3/2,2xy/2x-y=-3/10,x+y not= 0,2x-y not =
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In the attachment I have answered this problem.
The given equations are suitably modified and are solved by elimination method.
See the attachment for detailed solution.
The given equations are suitably modified and are solved by elimination method.
See the attachment for detailed solution.
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Answered by
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Given Equations,
2xy/(x + y) = 3/2
⇒ 2xy × 2 = 3(x + y)
⇒ 4xy = 3x + 3y
⇒ 3y + 3x = 4xy
∴ x = (4xy - 3y)/3 --------------------eq(i)
Now,
2xy/(2x - y) = -3/10
⇒ 2xy × 10 = -3(2x- y)
⇒ 20xy = -6x + 3y
⇒ 3y - 6x = 20xy ----------------------eq(ii)
Using the Substitution method for finding the value of x and y.
Putting the Value of eq(i) into the eq(ii),
3y - 6x = 20xy
⇒ 3y - 6(4xy - 3y)/3 = 20xy
∴ 3y - 8xy + 6y = 20xy
∴ 9y - 8xy = 20xy
∴ 9y = 28xy
∴ 28x = 9
∴ x = 9/28
Now, Putting the Value of the x in eq(ii), ∴ 3y - 6x = 20xy
∴ 3y = 20xy + 6x
∴ 3y = 20y(9/28) + 6(9/28)
45y/7 - 3y = -27/14
⇒ (45y - 21y)/7 = -27/14
⇒ 24y = -27/2
⇒ y = -9/16
Hence, the value of x is 9/28 and the value of y is -9/16.
Hope it helps.
2xy/(x + y) = 3/2
⇒ 2xy × 2 = 3(x + y)
⇒ 4xy = 3x + 3y
⇒ 3y + 3x = 4xy
∴ x = (4xy - 3y)/3 --------------------eq(i)
Now,
2xy/(2x - y) = -3/10
⇒ 2xy × 10 = -3(2x- y)
⇒ 20xy = -6x + 3y
⇒ 3y - 6x = 20xy ----------------------eq(ii)
Using the Substitution method for finding the value of x and y.
Putting the Value of eq(i) into the eq(ii),
3y - 6x = 20xy
⇒ 3y - 6(4xy - 3y)/3 = 20xy
∴ 3y - 8xy + 6y = 20xy
∴ 9y - 8xy = 20xy
∴ 9y = 28xy
∴ 28x = 9
∴ x = 9/28
Now, Putting the Value of the x in eq(ii), ∴ 3y - 6x = 20xy
∴ 3y = 20xy + 6x
∴ 3y = 20y(9/28) + 6(9/28)
45y/7 - 3y = -27/14
⇒ (45y - 21y)/7 = -27/14
⇒ 24y = -27/2
⇒ y = -9/16
Hence, the value of x is 9/28 and the value of y is -9/16.
Hope it helps.
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