Solve 2y/y-4 + 2y-5/y-3 = 25/3
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the value of y is 6 and 40/13
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by making the LCM equal,2x(x-3) +(2x-5)(x-4) / (x-4) (x-3)=25/33(4x2 -19x +20) = 25(x2-7x +12)12x2 - 57 x +60 = 25x2 - 175x + 30013x2 - 118 x + 240 =0now by splitting the middle term,13x2 -(78+40) x +240 =013x2 -78 x -40x +240 =013x ( x - 6) - 40 (x-6) =0(x-6) (13x -40)x = 6 and x = 40/13
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