Math, asked by upmanaveen, 1 year ago

Solve :-
2y³+y²-2y-1

Answers

Answered by Anonymous
8
Heya, dear user

Solution =

let the factor of
p (1 ) = 2(1)^3-2(1)-1
=0

If we divide 2y^3 + y - 2y - 1 by y - 1

we get , 2y^2 + 3y + 1

so,
=> (y + 1 ) ( 2y^2+ 3y + 1)
=> (y + 1 ) (2y^2 + 2y + y + 1)
=> (y + 1 ) {2y ( y + 1 ) +1 ( y + 1)}
=> ( y - 1 ) (y + 1 ) (2y + 1 )
answer

hope \:  \: its \: helps \: you
☺☺
Attachments:
Similar questions