Solve :-
2y³+y²-2y-1
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Heya, dear user
Solution =
let the factor of
p (1 ) = 2(1)^3-2(1)-1
=0
If we divide 2y^3 + y - 2y - 1 by y - 1
we get , 2y^2 + 3y + 1
so,
=> (y + 1 ) ( 2y^2+ 3y + 1)
=> (y + 1 ) (2y^2 + 2y + y + 1)
=> (y + 1 ) {2y ( y + 1 ) +1 ( y + 1)}
=> ( y - 1 ) (y + 1 ) (2y + 1 )
answer
☺☺
Solution =
let the factor of
p (1 ) = 2(1)^3-2(1)-1
=0
If we divide 2y^3 + y - 2y - 1 by y - 1
we get , 2y^2 + 3y + 1
so,
=> (y + 1 ) ( 2y^2+ 3y + 1)
=> (y + 1 ) (2y^2 + 2y + y + 1)
=> (y + 1 ) {2y ( y + 1 ) +1 ( y + 1)}
=> ( y - 1 ) (y + 1 ) (2y + 1 )
answer
☺☺
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