Question

solve : 3 (2×– 7) =5 (3× +8)​

Answer 1

Answer:

LCM of 3,6,9=18

Now let us change each of the given fraction into an equivalent fraction having 18 as the denominator.

(2/3)x(6/6)=(12/18)

and (5/6)x(3/3)=(15/18)

and (1/9)x(2/2)=(2/18)

Now,

=(12/18)+(15/18)−(2/18)

=(12+15−2)/18

=(27−2)/18

=(25/18)

=[1(7/18)]

Answer 2

                                                                    

Solve:

(i) 2 – 3/5            (ii) 4 + 7/8            (iii) 3/5 + 2/7          (iv) 9/11 – 4/15            (v) 7/10 + 2/5 + 3/2 

(vi) 2  + 3   (vii) 8  - 3

Answer:

(i) 2 – 3/5 = 2/1 – 3/5

                   = (2 * 5 – 3 * 1)/5                         [LCM (1, 5) = 5]

                   = (10 - 3)/5

                   = 7/5  

                   = 1             

(ii) 4 + 7/8 = 4/1 + 7/8          

                    = (4 * 8 + 7)/8                               [LCM (1, 8) = 8]

                    = (32 + 7)/8

                    = 39/8    

                    = 4       

(iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35                  [LCM (7, 5) = 35]

                         = (21 + 10)/35

                         = 31/35

(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165       [LCM (11, 15) = 165]

                             = (135 - 44)/165

                             = 91/165

(v) 7/10 + 2/5 + 3/2 = (7 * 1 + 2 * 2 + 3 * 5)/10

                                 = (7 + 4 + 15)/10

                                 = 26/10                        [26 and 10 are divided by 2]

                                 = 13/5

                                 = 2

(vi) 2  + 3  = 8/3 + 7/2

                      = (8 * 2 + 7 * 3)/6                  [LCM (2, 3) = 6]

                      = (16 + 21)/6

                      = 37/6

                      = 6

(vii) 8  - 3  = 17/2 – 29/8

                       = (17 * 4 – 29 * 1)/8            [LCM (2, 8) = 8]

                       = (68 - 19)/8

                      = 39/8

                      = 4