Solve (3+√3) (2+√2) 2
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(3x+√3)(2+√2)2
=3x(2+√2)+√3(2+√2)
=6x+3x√2+2√3+√3x2
=6x+3x√2+2√3+√6
=3x(2+√2)+√3(2+√2)
=6x+3x√2+2√3+√3x2
=6x+3x√2+2√3+√6
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