solve 3(n-4)+2 5(n-5)=5(n+2)+16
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I am not able to understand the question
what is between 2 and 5 in the middle of the question
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3(n-4)+10(n-5)=5(n+2)+16
3n-12+10n-50=5n+10+16
13n-62=5n+26
13n-5n=62+26
8n= 88
n= 88/8
n= 11
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