Math, asked by suvonitabiswas701, 2 months ago

Solve:3(x+1)-2(x-2)=3(x+4)-3x-15​

Answers

Answered by Anonymous
9

\large\sf\underline{Given\::}

  • \sf\:3(x+1) -2(x-2) =3(x+4) -3x-15

\large\sf\underline{To\:find\::}

  • Value of x

\large\sf\underline{Solution\::}

\sf\:3(x+1) -2(x-2) =3(x+4) -3x-15

  • Multiplying the terms

‎ ‎

\sf\implies\:3x+3 -2x+4 =3x+12 -3x-15

‎ ‎

  • Arranging terms

\sf\implies\:3x-2x+3+4 =3x-3x+12-15

  • Solving them

‎ ‎

\sf\implies\:x+7 = \cancel{3x}-\cancel{3x}+-3

\sf\implies\:x+7 =-3

‎ ‎

  • Transposing 7 to the other side

\sf\implies\:x =-3-7

\large{\mathfrak\red{\implies\:x\:=\:-10}}

_______________________

\large\sf\underline{Verifying\::}

\sf\:3(x+1) -2(x-2) =3(x+4) -3x-15

  • Substituting the value of x as (-10)

\sf\implies\:3(-10+1) -2(-10-2) =3(-10+4) -3(-10)-15

\sf\implies\:3(-9) -2(-12) =3(-6) +30 -15

\sf\implies\:-27 + 24 = -18 +30 -15

\sf\implies\:-3 = 12 -15

\sf\implies\:-3 = -3

\dag\:\underline{\sf Hence\:Verified\:}

_______________________

So the required value of x is \large{\underline{\boxed{\mathrm\pink{-10}}}}

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