Question

solve 3(x+4)_2(2_x)=4(2x_1)+7​

Answer 1

Answer:

3x+4x-4+2x=8x-4+7

→9x-8x=3+4

→x=8

Answer 2

$\huge {\boxed {\mathbb {QUESTION}}}$

solve

$3(x+4)-2(2-x)=4(2x-1)+7$

$\huge {\boxed {\mathbb {ANSWER}}}$

$3(x+4)-2(2-x)=4(2x-1)+7$

$\implies 3x+12-4+2x=8x-4+7$

$\implies 5x+8=8x+3$

$\implies 8x-5x=8-3$

$\implies 3x=5$

$\implies {\boxed {\boxed {x=\frac{5}{3}}}}$

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$IDENTITIES$

${(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$(a+b) (a-b)={a}^{2}-{b}^{2}$

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