Question

solve 3(x-4)^2-5(x-4)=12 using quadratic formula​

Answer 1

Hope u all like my answer ☺️

I don'ts think quadratic formula can be used...

Answer 2

$3 \times (x-4)^2-5 \times (x-4)-(12)=0 \\ ((3 \times ((x-4) {}^{2} ))-5 \times (x-4))-12 = 0 \\ 3 \times (x - 4)2 - 5 \times (x - 4) \\ \\ -168   +   -1   =   -169 \\ -84   +   -2   =   -86  \\     -56   +   -3   =   -59    \\   -42   +   -4   =   -46  \\     -28   +   -6   =   -34 \\      -24   +   -7   =   -31  \\     -21   +   -8   =   -29    \\ \\ (x - 7) \times (3x - 8) = 0 \\  x = 8/3 = 2.667$