Question

solve 3×[X+5]²+4×(X-2)-312=0​

Answer 1

Answer:

3×(x2+10x+25)+4x-8-312

3x2+30x+75+4x-320

3x2+34x-245

Answer 2

TIP:-

kindly ask the question in a little simple manner!!

QUESTION:-

3(x+5)²+4(x-2)-312=0

STEP BY STEP EXPLAINATION:-

=> OPENING THE BEACKET AND SQUARING THE BRACKETS WE GET.

=> 3(x²+10x+25)+4(x-2)-312=0

=>Now as we can see this has become litttle simpler.

and now

therefore we go.

=>3x²+30x+75+4x-8-312=0

=>3x²+34x-245=0

Now this is a quadratic equation!!

you can easily solve it by following methods.

• SHREEDHARACHARYA'S FORMULA
• COMPLETE THE SQUARE METHOD.
• BREAK THE MIDDLE TERM METHOD.

TO FOR THE SIMPLICITY TAKE

BREAK THE MIDDLE TERM FORMULA :-

(x-5)(x+49/3)

therefore,.

x=5

x=-49/3

VERIFICATION:-

x²(5-49/3)x-245/3=0

ans!!