Math, asked by safzzufi2001, 11 months ago

Solve 3/x+y+2/x-y=3,2/x+y+3/x-y=11/3

Answers

Answered by spiderman2019
12

Answer:

x = 2, y  = 1

Step-by-step explanation:

Multiply first equation by 2 and second equation by 3 and subtract.

(6/x+y + 4/x-y) - (6/x+y + 9/x-y) = 6  - 11

- 5/x-y = - 5

x-y = 1  ----------------> Equation 1.

Multiply first equation by 3 and second equation by 2 and subtract.

(9/x+y + 6/x-y) - (4/x+y + 6/x-y) = 9 - 22/3

5/x+y = 5/3

x+ y = 3 ============> equation 2

Add equation 1 and equation 2

x -y = 1

x + y = 3

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2x = 4 => x = 2,

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substitute value of x in equation 1 =>

2 - y = 1 ===> y = 1.

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