Solve 30 sum plzz
I will mark u brainlist ok so plz solve
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let 1/(2x+3y) =A, and 1/(3x-2y) =B,
then the equation becomes,
A/2 + 12B/7 = 1/2,
(7A+24B)/14 =1/2,
7A+24B=1/2 ×14,
then
7A+24B=7,........eq(1),
also
7A+4B=2,.............eq(2),
now subtract eq(2) from eq(1), we have
24B-4B=7-2,
20B=5,
B=5/20,
B=1/4,
but B=1/(3x-2y),
then
1/(3x-2y) =1/3,
3x-2y=3,.…..........eq(3),
now put the value of B in eq(2), we get
7A+4×1/4 =2,
7A+1=2,
then
7A=2-1=1,
then
A=1/7,
but
A=1/(2x+3y),
so
1/(2x+3y) =1/7,
2x+3y=7,.............eq(4),
so now on solving eq(3) and eq(4), u will get the values of x and y,
now i hope u can easily solved these two equations.....
then the equation becomes,
A/2 + 12B/7 = 1/2,
(7A+24B)/14 =1/2,
7A+24B=1/2 ×14,
then
7A+24B=7,........eq(1),
also
7A+4B=2,.............eq(2),
now subtract eq(2) from eq(1), we have
24B-4B=7-2,
20B=5,
B=5/20,
B=1/4,
but B=1/(3x-2y),
then
1/(3x-2y) =1/3,
3x-2y=3,.…..........eq(3),
now put the value of B in eq(2), we get
7A+4×1/4 =2,
7A+1=2,
then
7A=2-1=1,
then
A=1/7,
but
A=1/(2x+3y),
so
1/(2x+3y) =1/7,
2x+3y=7,.............eq(4),
so now on solving eq(3) and eq(4), u will get the values of x and y,
now i hope u can easily solved these two equations.....
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