Question

Solve 32(9^2x)−243(16^x) > 0.​

Answer 1

Answer:

$32 \times (81 \times 2x) - 243 \times 16x = 0 \\ 32 \times (162 \times ) - 3888x = 0 \\ 32 \times 162x - 3888x = 0 \\ 5184x - 3888x = 0 \\ 1296x = 0 \\ x = 0$