Math, asked by nalsivas4u8dhara, 1 year ago

Solve: 36x^2-12ax+(a^2-b^2)=0

Answers

Answered by abhi178
474
36x² -12ax +( a²-b²) = 0

(6x)² - 2.(6x).a + a² -b² = 0

{6x - a}² - b² = 0

use formula ,
a² -b² = (a - b)(a + b)

{6x -a -b}{6x -a + b} =0

x = (a + b)/6 , (a - b)/6
Answered by adith244pbxpqz
211

36x² -12ax +( a²-b²) = 0

(6x)² - 2.(6x).a + a² -b² = 0

{6x - a}² - b² = 0

use formula ,

a² -b² = (a - b)(a + b)  

{6x -a -b}{6x -a + b} =0

x = (a + b)/6 , (a - b)/6

i hope u understand

Similar questions