Question

solve 37x +41y =70 41x+37y=86 by using alimination method

Answer 1

Answer:

37x +41y =70 .....(1)

41x+37y=86......(2)

BY ELIMINATION METHOD

MULTIPLY EQ(1) BY 41 AND EQ(2) BY 37

==> 1517X + 1681Y = 2870

      1517X + 1369Y = 3182

==>    312Y = -312

==> Y = -312/312

==> Y = -1

PUTTING VALUE OF Y IN EQ(1)

==> 37X+41(-1) = 70

==> 37X-41 = 70

==> 37X = 111

==> X = 111/37

==> X = 3

SO, X= 3 AND Y = -1

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Answer 2

Answer:

Step-by-step explanation:

41x+53y=135------------ (1)

53x+41y=147-------------(2)

by elimination method,

multiply 41 in eq.(1) and multiply 53 in eq.(2),

(41x+53y=135)×41

(53x+41y=147)×53

1681x+2173y=5535

2809x+2173y=7791

- - -

__________________(by subtracting)

-1128x = -2256. (2173y-2173y cancelled)

x = -2256/-1128(- and - is cancelled

x = 2

put the value of x in eq. (2),

53x+41y=147

53×2+41y=147

106+41y=147

41y=147-106

41y=41

y=41/41

y=1

so the value of x=2

y=1

Ans.

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