Physics, asked by ravi34287, 1 year ago

solve 3rd question please help?

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Answered by Shubhendu8898
13

Given,

The  displacement x of  a  particle at any  point is related  to velocity as,

v=\sqrt{2x+9}

v^2=2x+9\\\;\\v^2-9=2x\\\;\\v^2-3^2=2x

On comparing  with third  equation of  motion , v^2-u^2=2as

2a=2\\\;\\a=1\;m/s^2

Here  a  is  the  acceleration of  particle, u is  initial velocity and  v is  final velocity. s=x displacement  of  particle.


Answered by Anonymous
3
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