solve 3x/2-5y/3=-2 and x/3+y/2=13/6
Answers
Answer:
−
3
5y
=−2 ……………………..(1)
\frac{x}{3}+\frac{y}{2}=\frac{13}{6}
3
x
+
2
y
=
6
13
……………………….(2)
Consider equation \frac{3 x}{2}-\frac{5 y}{3}=-2
2
3x
−
3
5y
=−2
By taking LCM for the denominator 2 and 3 we get the LCM as 6
\begin{gathered}\begin{array}{l}{\frac{3 x}{2} \times \frac{6}{6}=\frac{9 x}{6}} \\ {\frac{5 y}{3} \times \frac{6}{6}=\frac{10 y}{6}} \\ {\frac{9 x}{6}-\frac{10 y}{6}=-2}\end{array}\end{gathered}
2
3x
×
6
6
=
6
9x
3
5y
×
6
6
=
6
10y
6
9x
−
6
10y
=−2
9x – 10y = -12 ……………………….. (3)
Consider equation 2
\frac{x}{3}+\frac{y}{2}=\frac{13}{6}
3
x
+
2
y
=
6
13
By taking LCM for the denominator 3 and 2 we get the LCM as 6
\begin{gathered}\begin{array}{l}{\frac{x}{3} \times \frac{6}{6}=\frac{2 x}{6}} \\ {\frac{y}{2} \times \frac{6}{6}=\frac{3 y}{6}} \\ {\frac{2 x}{6}+\frac{3 y}{6}=\frac{13}{6}}\end{array}\end{gathered}
3
x
×
6
6
=
6
2x
2
y
×
6
6
=
6
3y
6
2x
+
6
3y
=
6
13
2x + 3y = 13 …………………………(4)
By solving equation (3) and (4) we get
2x = 13-3y
x=13-3y/2 …………………………(5)
Put the value of x in eqn 3 we get
9[13-3y/2] – 10y =-12
117-27y-20y = -24 [By taking LCM and solving it]
117-47y=-24
-47y=-24-117
-47y=-141
Y=-141/-47
Y=3
Now put the value of y =3 in (5)
x=13-3(3)/2
x=13-9/2
x=4/2
x=2
Therefore we have x=2 and y=3
Answer:
Step-by-step explanation:
Here,
It's given
3x/2 - 5y/3 = - 2
3x - 5y = - 2 * 2 *3 ( transferring the 2 and 3)
3x - y = - 12 + 5y
x = - 12 +5y /3
Now,
X/3 + y/2 = 13/6
-12 + 5y/3/3 + y/2 = 13/6
-12 +5y /9 + y/2 =13 /6
You do all calculations,
It's easy, if you are not getting tell me
And at last
9y = 63
Y = 7
Now,
X /3 + y /2 = 13 /6
X/3 + 7/2 =13 /6
2x +21/6 = 13/6
2x + 21 = 13
2x = 8
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