Math, asked by ItzInnocentPrerna, 1 month ago

Solve 3x + 2y = 11 and 2x + 5y = 8 with Elimination Method.​

Answers

Answered by swayamraj2507
1

Answer:

Step by Step explanation:

Multiply eq. 1 with 2 and eq. 2 with 3, and then take sub. of both the eqs.

Thus,

6x+4y=11

6x+15y=24

- - -

________

-11y= -13

11y=13

y =  \frac{13}{11}

Now put the value of y in any eq.

3x+2(13/11)=11

3x+26/11=11

LCM=11

33x+26=121

33x=121-26

33x=95

x=95/33

I HOPE THIS WILL HELP YOU

Answered by rehanchilangi123
1

Step-by-step explanation:

Answer:

Step by Step explanation:

Multiply eq. 1 with 2 and eq. 2 with 3, and then take sub. of both the eqs.

Thus,

6x+4y=11

6x+15y=24

- - -

________

-11y= -13

11y=13

y = \frac{13}{11}y=

11

13

Now put the value of y in any eq.

3x+2(13/11)=11

3x+26/11=11

LCM=11

33x+26=121

33x=121-26

33x=95

x=95/33

I HOPE THIS WILL HELP YOU

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