Question

solve
3x+2y=5
2x-3y=7 by elimination method
​

Answer 1

$\color{red}{Question}$

solve

3x+2y=5

2x-3y=7 by elimination method

$\bold{\boxed{ Step-by-step\: explanation: }}$

3x+2y=5 ➝ (i)

2x-3y=7 ➝ (ii)

By elimination method:

1. x2 ➝ 6x + 4y = 10

2. x3 ➝ 6x - 9y = 21

...............(-). (+). (-).

................... 13y = -11.

.°. y = -11/13

Putting y = -11/13 in eqn $\bold{\boxed{1 -}}$

3x + 2y (-11/13) = 5

= 3x + (-22/13) = 5 = 3x - 22/13 = 5

= 3x = 5 + 22/13 = 3x = 65+22/13

= x = 87/13 × 1/3

= 29/13 × 1/1 = 29/13

$\color{green}{Done\:! }$

Answer 2

Answer:

y = 7/5 x = (-1/3)

Step-by-step explanation:

lets multiply the coefficient of x of both equation by each other ,

multiply by 2----3x + 2y =5

multiply by 3 ---2x - 3y = 7

6x + 2y = 5-------------equation 1

6x - 3y = 7-------------equation 2

change the sign of last equation and solve

y will be 7/5

put the value of y in equation 1

you will get the answer of x , and it will be (-1/3)