Question

solve 3x+5y=15
and 5x+2y=10
​

Answer 1

Answer:

[1] 3x + 5y = 15

[2] 5x + 2y = 10Solve equation [2] for the variable y

[2] 2y = -5x + 10

[2] y = -5x/2 + 5

Plug this in for variable y in equation [1]

[1] 3x + 5•(-5x/2+5) = 15

[1] -19x/2 = -10

[1] -19x = -20

Solve equation [1] for the variable x

[1] 19x = 20

[1] x = 20/19

By now we know this much :

x = 20/19

y = -5x/2+5

Use the x value to solve for y

Solve equation [2] for the variable y

[2] 2y = -5x + 10

[2] y = -5x/2 + 5

Plug this in for variable y in equation [1]

[1] 3x + 5•(-5x/2+5) = 15

[1] -19x/2 = -10

[1] -19x = -20

Solve equation [1] for the variable x

[1] 19x = 20

[1] x = 20/19

By now we know this much :

x = 20/19

y = -5x/2+5

Use the x value to solve for y

y = -(5/2)(20/19)+5 = 45/19

Solution :

{x,y} = {20/19,45/19}

y = -(5/2)(20/19)+5 = 45/19

Solution :

{x,y} = {20/19,45/19}

Answer 2

Answer:

(x,y) => 20/19, 45/19

Step-by-step explanation:

3x+5y=15. eqn 1

5x+2y=10. eqn 2

eqn 1 multiple 2

2*5=>25x+10y=50

1*2=> 6x+10y=30

=>19x. =20

x =20/19

substitute x=20/19in eqn 2

5x+2y=10

5(20/19)+2y =10

y= 45/19.

I hope Iam correct