Solve : 3x + 8 >2 when,
(1) x is an integer
(2) x is a real number.PLZZZ DO IT REALL FASTT!!!
DevilDoll12:
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Answered by
4
3x+8)/(x+2)
=(3x+ 6 + 2)/(x+2)
= 3 + 2/(x+2) as X is an integer 0 or an other integer 2/(x+2)
x=0
(3x+8)/(x+2) = 8/2 = 4
I think it's help U :-)
=(3x+ 6 + 2)/(x+2)
= 3 + 2/(x+2) as X is an integer 0 or an other integer 2/(x+2)
x=0
(3x+8)/(x+2) = 8/2 = 4
I think it's help U :-)
Thank U for brainliest !!!
Your welcome
Answered by
0
mene reaction puchha....
smjane ko nahi bola yrr.......
=_=.. =_=..
plz make your answer correct.._/\_
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