Question

Solve 3x+y+1=0 and 2x-3y+8=0 by substitution method

Answer 1

Heya pankaj.....

3x+y+1=0---------(1)
2x-3y+8=0---------(2)

From (1)
Y=-1-3x-------(3)

Put y in (2)
2x+3(1+3x)+8=0
2x+3+9x+8=0
11x+11=0
X=-1

Put x in (3)
Y=-1+3
Y=2

@skb

Answer 2

Concept introduction:

Finding the answer of any factor from one formula of another variable is the first step in the replacement technique. For instance, if there are two equations, $x+y=7$ and $x-y=8$, we may deduce that $x=7-y$ from the first equation.

Given:

Here it is given that the two equations are $3x+y+1=0$ and $2x-3y+8=0$.

To find:

We have to find the value of $x$ and $y$.

Solution:

According to the question,

$3x+y+1=0---------(1)\\2x-3y+8=0---------(2)$

$From (1)\\Y=-1-3x-------(3)$

Put

$y in (2)\\2x+3(1+3x)+8=0\\2x+3+9x+8=0\\11x+11=0\\X=-1$

Put $x$ in $(3)$

$Y=-1+3Y=2$

Final answer:

Hence, the final answer of the question is => $X=-1, Y=2$.

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