Question

solve 3x²=10x+4 using quadratic equation.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$3x^2 = 10 x +4 \\\\\implies 3x^2 -10 x -4 =0\\\\\text{Apply quadratic formula,} ~ x = \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a} .\\\\\text{In this case,}~ a = 3, ~b= -10, ~c=-4 \\\\x = \dfrac{-(-10) \pm \sqrt{(-10)^2 - 4 \cdot 3 (-4)}}{2(3)}\\\\\\\implies x = \dfrac{10 \pm \sqrt{100+48}}{6} = \dfrac{10\pm\sqrt{148}}6 = \dfrac{10 \pm 2\sqrt{37}}{6} = \dfrac{5\pm\sqrt{37}}3$

$\text{Hence the roots are} , ~ x = \dfrac{ 5 + \sqrt{ 37}}3 , ~ x = \dfrac{5- \sqrt{37}}3$