Question

solve 3x2-20x-23=0 by formula method​

Answer 1

Step-by-step explanation:

3x²-20x-23=0

a=3, b=-20, c=-23

x=-b±root of (b²-4ac) whole divided by 2a

x=-20± root of [(-20)²-4(3)(-23)] whole divided by 2(3)

x=-20±root of (400+276) whole divided by 6

x=(-20±√676) whole divided by 6

x=(-20±26)/6

x=(-10+13)/3 and x=(-10-13)/3

x=1 and x=-23/3