Math, asked by navarasan50, 11 months ago

solve 3x²-5x+2=0 by using completing the square method​

Answers

Answered by Anonymous
106

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3x² -5x +2 =0

Now divide the x² coefficient throughout,

⇒x²- 5x/3+2/3=0

Divide the coefficient of x by 2, and square it and add it and subtract it in the equation,

⇒x²-5x/3+2/3+25/36 -25/36 =0

⇒x²-5x/3+25/36 =1/36

⇒(x-5/6)²=(1/6)²

⇒x-5/6=plus or minus 1/6

x-5/6=1/6      (or) x-5/6= -1/6 ⇒x= -1/6+5/6⇒x=4/6 ⇒x=2/3.

x=1.

x=1(or)2/3.

Hope it will help you.

Answered by gakulgjn
6

Answer:

X=2/3 or x=1

Step-by-step explanation:

3x²-5x+2=0

=3x²-(3+2)X+2

=3x²-3x-2x+2

=3x(x-1)-2(x-1)

=(3x-2)(x-1)

=>x=2/3 or x=1

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