Math, asked by akhilhimnad62, 1 year ago

solve 4^log X = 32- x^log4​

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Answers

Answered by Thanujmullaguri
1

i hope this helps you solve the problem plz mark as brainliest

substitution is the best for these type of mcq sums

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Answered by pinquancaro
3

Option A - the solution is 100.

Step-by-step explanation:

Given : Expression 4^{\log x} = 32- x^{\log 4}

To find : Solve the expression ?

Solution :

Expression 4^{\log x} = 32- x^{\log 4}

Using logarithmic property, x^{\log a}=a^{\log x}

4^{\log x} = 32- 4^{\log x}

Take like terms together,

4^{\log x}+4^{\log x}= 32

2(4^{\log x})= 32

4^{\log x}= 16

4^{\log x}=4^2

Compare the bases,

\log_{10} x=2

Using logarithmic property, \log_a x=y\Rightarrow a^y=x

Here, a=10, x=x and y=2

x=10^2

x=100

Therefore, option A is correct.

#Learn more

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