Solve : 4(y + 2) – 5(2y + 1) = -3y + 1
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Answered by
7
Correct Question :-
Solve —
Correct Answer :-
We can solve the Equation as follows;
$ \to \sf{4y+8-5\left(2y+1\right)=-3y+1 }$
$ \to \sf{4y+8-10y-5=-3y+1 }$
$ \to \sf{-6y+8-5=-3y+1 }$
$ \to \sf{-6y+3=-3y+1 }$
$ \to \sf{-6y+3+3y=1 }$
$ \to \sf{-3y+3=1 }$
$ \to \sf{-3y=1-3 }$
$ \to \sf{-3y=-2 }$
@MrCyber
Answered by
1
Answer:
We can solve the Equation as follows;
→4y+8−5(2y+1)=−3y+1
→4y+8−10y−5=−3y+1
→−6y+8−5=−3y+1
→−6y+3=−3y+1
→−6y+3+3y=1
→−3y+3=1
→−3y=1−3
→−3y=−2
→y=
−3
−2
→y=
3
2
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