Math, asked by akarsh209, 1 year ago

solve...............

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Answered by rakeshmohata
1
Hope u like my process
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 =  >  \:  {18}^{4x - 3} =  {(54 \sqrt{2}) }^{3x - 4}  \\  \\ or. \:  \:  {(2 \times  {3}^{2}) }^{4x - 3}  = (2 \times  {3}^{3}  \times  \sqrt{2} )^{3x - 4}  \\  \\ or. \:  \:   {( {( \sqrt{2}) }^{2} \times  {3}^{2} ) }^{4x - 3}  =  { {(( \sqrt{2}) }^{3} \times  {3}^{3})  }^{3x - 4}  \\  \\ or. \:  \:  {(3 \sqrt{2}) }^{2(4x -  3)}  =  {(3 \sqrt{2}) }^{3(3x - 4)}  \\  \\ so...comparingly \:  \: we \:  \: get... \\  \\ =  >  2(4x - 3) = 3(3x - 4) \\  \\ or. \:  \: 8x - 6 = 9x - 12 \\  \\ or. \:  \: 9x - 8x =   12  -  6 \\  \\ or. \:  \: x =  6 ....(answer)...
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Answered by tejnagpal
1
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